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\lhead{\color{blue} \Large Lecture Notes}
\chead{\color{black} \LARGE Differentiation 5}
\rhead{\large page   \ \thepage}
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\lfoot{\small   \copyright $\;$ copyright  Hidegkuti,  Powell,  2009}
\rfoot{\small   Last revised: March 20, 2012}
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\begin{document}


\begin{center}
{\Large Practice Problems\bigskip }\bigskip
\end{center}

Differentiate each of the following functions. \ \ Assume that $a$ is a
constant. \ \ Please note that the inverse function for $\sin x,$ \
(sometimes denoted by $\sin ^{-1}x)$ \ is denoted by $\arcsin x$
here.\bigskip \bigskip

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\begin{enumerate}
\item $f\left( x\right) =e^{3-x}$\medskip

\item $f\left( x\right) =\arctan x$\medskip

\item $f\left( x\right) =\sqrt{a^{2}-\sin ^{2}x}$\medskip

\item $f\left( x\right) =\arcsin 3x$

\item $f\left( x\right) =2^{5x^{2}+1}$\medskip

\item $f\left( x\right) =\ln \left( 5x^{2}-8x+3\right) $\medskip

\item $f\left( x\right) =-\dfrac{\sin x\cos x}{2}+\dfrac{x}{2}$\medskip

\item $f\left( x\right) =e^{-x^{2}}$\medskip

\item $f\left( x\right) =\cos x\cdot 10^{\sin x}$\medskip

\item $f\left( x\right) =-\dfrac{1}{4}e^{-2x}-\dfrac{1}{2}xe^{-2x}$\medskip

\item $f\left( x\right) =\dfrac{1}{2}\left( \arcsin x\right) ^{2}+e^{5}$%
\medskip

\item $f\left( x\right) =10\sin 2x\cos 2x$\medskip

\item $f\left( x\right) =\dfrac{1}{2}x^{2}\ln x-\dfrac{1}{4}x^{2}$\medskip

\item $f\left( x\right) =\arctan \left( 10x\right) $\medskip

\item $f\left( x\right) =\ln \left( \tan x\right) $\medskip

\item $f\left( x\right) =\dfrac{x}{x+1}$\medskip

\item $f\left( x\right) =\arctan \left( \dfrac{x}{x+1}\right) $\medskip

\item $f\left( x\right) =\arcsin \left( x^{2}-1\right) $\medskip

\item $f\left( x\right) =\log _{3}\left( \sec x\right) $\medskip

\item \ $f\left( x\right) =\cos ^{-1}\left( x^{6}\right) $\medskip

\item \ $f\left( x\right) =2^{\sin \left( -5x\right) }$\medskip

\item $f\left( x\right) =e^{\sin x+\cos x}$\medskip

\item $f\left( x\right) =\sin \left( \ln \left( x^{3}\right) \right) $%
\medskip
\end{enumerate}

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\begin{center}
{\Large Practice Problems - Answers \bigskip }\bigskip \bigskip
\end{center}

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\begin{enumerate}
\item $f^{\prime }\left( x\right) =-e^{3-x}$\medskip

\item $f^{\prime }\left( x\right) =\dfrac{1}{x^{2}+1}$\medskip

\item $f^{\prime }\left( x\right) =-\dfrac{\cos x\sin x}{\sqrt{a^{2}-\sin
^{2}x}}$\medskip

\item $f^{\prime }\left( x\right) =\dfrac{3}{\sqrt{1-9x^{2}}}$\medskip

\item $f^{\prime }\left( x\right) =10x\left( \ln 2\right) 2^{5x^{2}+1}$%
\medskip

\item $f^{\prime }\left( x\right) =\dfrac{10x-8}{5x^{2}-8x+3}$\medskip

\item $f^{\prime }\left( x\right) =\sin ^{2}x$\medskip

\item $f^{\prime }\left( x\right) =-2xe^{-x^{2}}$\medskip

\item $f^{\prime }\left( x\right) =10^{\sin x}\left[ -\sin x+\left( \ln
10\right) \cos ^{2}x\right] $

\item $f^{\prime }\left( x\right) =xe^{-2x}$\medskip 

\item $f^{\prime }\left( x\right) =\dfrac{\arcsin x}{\sqrt{1-x^{2}}}$%
\medskip 

\item $f^{\prime }\left( x\right) =20\cos ^{2}2x-20\sin ^{2}2x=20\cos 4x$%
\medskip 

\item $f^{\prime }\left( x\right) =x\ln x$\medskip 

\item $f^{\prime }\left( x\right) =\dfrac{10}{100x^{2}+1}$\medskip 

\item $f^{\prime }\left( x\right) =\dfrac{\tan ^{2}x+1}{\tan x}=\tan x+\cot x
$\medskip 

\item $f^{\prime }\left( x\right) =\dfrac{1}{\left( x+1\right) ^{2}}$

\item $f^{\prime }\left( x\right) =\dfrac{1}{2x^{2}+2x+1}$

\item $f^{\prime }\left( x\right) =\dfrac{2x}{\sqrt{1-\left( x^{2}-1\right)
^{2}}}$

\item $f^{\prime }\left( x\right) =\dfrac{\tan x}{\ln 3}$

\item \ $f^{\prime }\left( x\right) =-\dfrac{6x^{5}}{\sqrt{1-x^{12}}}$

\item $f^{\prime }\left( x\right) =-5\left( \ln 2\right) \dfrac{\cos 5x}{%
2^{\sin 5x}}$

\item $f^{\prime }\left( x\right) =e^{\cos x+\sin x}\left( \cos x-\sin
x\right) $

\item $f^{\prime }\left( x\right) =\allowbreak \dfrac{3}{x}\cos \left( \ln
x^{3}\right) $
\end{enumerate}

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