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\lhead{\Large \color{blue} Lecture Notes}
\chead{ \LARGE Are you ready for calculus 2?}
\rhead{\large  page \thepage}
\lfoot{\small   \copyright $\;$  Hidegkuti  2012}
\rfoot{\small Last revised: January 2, 2015}
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\begin{document}


\begin{enumerate}
\item Differentiate each of the following.%
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a) \ $f\left( x\right) =3x^{4}-x^{3}+4x^{2}-x+7$\medskip

b) \ $f\left( x\right) =\sqrt[5]{2x^{6}+5x^{2}+1}$\medskip

c) \ $f\left( x\right) =\cos x+x\sin x$\medskip

d) \ $f\left( x\right) =\cos \left( 2x-\dfrac{\pi }{2}\right) $\medskip

e) \ $f\left( x\right) =\left( 3x-1\right) ^{100}$\medskip

f) \ $f\left( x\right) =\dfrac{-x+5}{\sqrt{x^{2}+1}}$\medskip

g) \ $f\left( x\right) =\dfrac{x^{2}+1}{\sin 5x}$\medskip

h) \ $f\left( x\right) =\cot \left( \dfrac{\pi }{2}x\right) $\medskip

i) \ $f\left( x\right) =\sqrt{1+\sqrt{x}}$\medskip

j) \ $f\left( x\right) =\tan 3x$\medskip

k) \ $f\left( x\right) =\tan \left( 3x^{2}\right) $\medskip

l) \ $f\left( x\right) =\sec x+\tan x$\medskip\ 
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\item Find the exact value of each of the following. \ 
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a) \ $\sin \left( \dfrac{-7\pi }{3}\right) $

b) \ $\sin \left( \cos ^{-1}\left( -\dfrac{1}{2}\right) \right) $

c) \ $\tan ^{-1}\left( \tan \left( \dfrac{7\pi }{3}\right) \right) $ \ \ 
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\item What is the exact value of $\sin x$ if $\tan x=-2$?

\item Assume that for all real numbers $x$ and $y,$%
\begin{eqnarray*}
\sin ^{2}x+\cos ^{2}x &=&1\text{ \ } \\
\sin \left( x+y\right) &=&\sin x\cos y+\cos x\sin y\text{ \ \ and \ } \\
\cos \left( x+y\right) &=&\cos x\cos y-\sin x\sin y
\end{eqnarray*}%
Prove each of the following.%
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a) \ $\sin \left( x-y\right) =\sin x\cos y-\cos x\sin y$

b) \ $\cos 2x=2\cos ^{2}x-1$

c) \ $\cos 2x=1-2\sin ^{2}x$

d) \ $\sin x=\pm \sqrt{\dfrac{1-\cos 2x}{2}}$

e) \ $\tan \left( x+y\right) =\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

f) \ $\sec ^{2}x=1+\tan ^{2}x$

g) \ $\cos ^{2}x=\dfrac{1}{2}\left( \cos 2x+1\right) $

h) \ $\dfrac{\sin x}{1+\cos x}=\dfrac{1-\cos x}{\sin x}$ \ \ 
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\item Simplify each of the following%
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a) \ $\sin \left( \sin ^{-1}x\right) $

b) \ $\cos \left( \sin ^{-1}x\right) $

c) \ $\sin \left( \tan ^{-1}x\right) $

d) $\tan \left( \cos ^{-1}x\right) $ \ \ 
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\item Prove that the following expressions are all equivalent. 
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$A=\sqrt{\dfrac{1+\sin x}{1-\sin x}}$

$B=\dfrac{1+\sin x}{\cos x}$

$C=\sec x+\tan x$

$D=\dfrac{\cos x}{1-\sin x}$

$E=\dfrac{1}{\sec x-\tan x}$ 
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(Hint: prove that $A=B$ and that $B=C$ and that $B=D$ and then $D=E$)

\item Prove each of the following.%
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a) \ $\log _{24}90=\dfrac{\ln 2+2\ln 3+\ln 5}{3\ln 2+\ln 3}$

b) \ $2\log _{10}\left( 2x\right) +\log _{10}\left( 25x\right) -3\log
_{10}\left( 0.1x\right) =5$

c) \ $\log _{2}3\cdot \log _{3}4\cdot \log _{4}5\cdot \log _{5}6\cdot \log
_{6}7\cdot \log _{7}8=3$

d) \ $\log _{3}\left\vert \tan x\right\vert =-\log _{3}\left\vert \cot
x\right\vert $ 
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\item Compute each of the following limits.%
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a) \ $\lim\limits_{x\rightarrow \infty }\dfrac{\sin 5x}{x}$\medskip

b) \ $\lim\limits_{x\rightarrow 0}\dfrac{\sin 5x}{x}$\medskip

c) \ $\lim\limits_{x\rightarrow 0}\dfrac{\sqrt{9+x}-3}{x}$\medskip

d) \ $\lim\limits_{x\rightarrow 2}\dfrac{\dfrac{1}{x}-\dfrac{1}{2}}{x-2}$%
\medskip

e) \ $\lim\limits_{x\rightarrow 2}\dfrac{1}{x^{2}-4}$\medskip

f) \ $\lim\limits_{x\rightarrow 2^{-}}\dfrac{1}{x^{2}-4}$\medskip

g) \ $\lim\limits_{x\rightarrow 0}\dfrac{\cos x+1}{x-\pi }$\medskip

h) \ $\lim\limits_{x\rightarrow 0^{+}}\log _{3}x$\medskip

i) \ \ $\lim\limits_{x\rightarrow \infty }\tan ^{-1}x$\medskip

j) \ $\lim\limits_{x\rightarrow 1^{-}}\dfrac{x^{2}+x-2}{x^{2}-1}$\medskip

k) \ $\lim\limits_{x\rightarrow -1^{-}}\dfrac{x^{2}+x-2}{x^{2}-1}$\medskip

l) \ $\lim\limits_{x\rightarrow \infty }\dfrac{x^{2}+x-2}{x^{2}-1}$\medskip\
\ 
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\item Use implicit differentiation to differentiate each of the following.%
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a) $\left( x^{2}-y^{2}\right) ^{4}=2xy^{2}$

b) $\left( x+y\right) ^{3}=\sin x-\sin y$ 
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\item Prove that $\dfrac{d\left( x^{2}-x\right) }{dx}=2x-1$, using the
definition of the derivative as the limit of the differential quotient.

\item Prove that if $f\left( x\right) =\sin ^{-1}x$ then $f^{\prime }\left(
x\right) =\dfrac{1}{\sqrt{1-x^{2}}}$

\item Evaluate each of the following integrals.%
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a) \ $\dint \dfrac{1}{x^{2}+1}~dx$\medskip

b) \ $\dint \dfrac{x^{2}}{x^{2}+1}~dx$\medskip

c) \ $\dint \sin 5x~dx$\medskip

d) \ $\dint \dfrac{1}{-x+2}~dx$\medskip

e) \ $\dint \left( 3x-1\right) ^{10}~dx$\medskip

f) \ $\dint \dfrac{1}{\sqrt{1-9x^{2}}}~dx$\medskip

g) \ $\dint \dfrac{1}{x-5}~dx$\medskip

h) \ $\dint 3-\dfrac{2}{x-5}~dx$\medskip

i) \ $\dint \dfrac{3x-17}{x-5}~dx$\medskip\ \ 
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\item Express each of the following in terms of the variable given.

a) \ Let $a$ be the side of a regular triangle. \ Express its area in terms
of $a$.

b) \ Let $h$ be the height of a regular triangle. \ Express its area in
terms of $h$.

c) \ Let $A$ be the area of a square. \ Express its perimeter in terms of $%
A. $

d) \ Let $c$ be the hypotenuse of an isosceles right triangle. \ We write a
semicircle on each of its sides as shown on the picture below. \ Express the
area of the shaded region in terms of $c$.\FRAME{dtbpF}{1.7988in}{1.7824in}{%
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\end{enumerate}

\pagebreak

\begin{center}
{\LARGE Answers\bigskip }
\end{center}

\begin{enumerate}
\item a) \ $f^{\prime }\left( x\right) =12x^{3}-3x^{2}+8x-1$ \ \ \ \ b) \ \ $%
f^{\prime }\left( x\right) =\dfrac{12x^{5}+10x}{5\left(
2x^{6}+5x^{2}+1\right) ^{4/5}}=\dfrac{1}{5}\dfrac{12x^{5}+10x}{%
2x^{6}+5x^{2}+1}\sqrt[5]{2x^{6}+5x^{2}+1}\medskip $

c) \ $f^{\prime }\left( x\right) =x\cos x$ \ \ \ \ \ \ d) \ $f^{\prime
}\left( x\right) =-2\sin \left( 2x-\dfrac{\pi }{2}\right) $ \ \ \ \ \ \ \ \
e) \ $f^{\prime }\left( x\right) =300\left( 3x-1\right) ^{99}\medskip $

f) \ $f^{\prime }\left( x\right) =\dfrac{-5x-1}{\left( x^{2}+1\right) ^{3/2}}
$ \ \ \ \ \ \ \ \ \ g) $\ f^{\prime }\left( x\right) =\dfrac{2x\sin
5x-5\left( x^{2}+1\right) \cos 5x}{\sin ^{2}5x}\medskip $

h) \ $f^{\prime }\left( x\right) =-\dfrac{\pi }{2}\csc ^{2}\left( \dfrac{\pi 
}{2}x\right) =-\dfrac{\pi }{2}\left( \cot ^{2}\dfrac{\pi }{2}x+1\right) $ \
\ \ \ \ \ \ \ \ i) \ $f^{\prime }\left( x\right) =\dfrac{1}{4\sqrt{x}\sqrt{%
\sqrt{x}+1}}\medskip $

j) \ $f^{\prime }\left( x\right) =3\sec ^{2}3x=3\tan ^{2}3x+3\medskip $ \ \
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ k) \ $f^{\prime }\left(
x\right) =6x\left( \tan ^{2}\left( 3x^{2}\right) +1\right) =6x\sec
^{2}\left( 3x^{2}\right) $

l) \ $f^{\prime }\left( x\right) =\sec x\tan x+\sec ^{2}x=\tan ^{2}x+1+%
\dfrac{\sin x}{\cos ^{2}x}$

\item a) $-\dfrac{\sqrt{3}}{2}$ \ \ \ \ \ \ b) \ $\dfrac{\sqrt{3}}{2}$ \ \ \
\ \ \ \ \ \ c) \ $\dfrac{\pi }{3}$

\item $\pm \dfrac{2\sqrt{5}}{5}$

\item see solutions

\item a) \ $x$ \ \ \ \ \ b) \ $\sqrt{1-x^{2}}$ \ \ \ \ c) \ $\dfrac{x}{\sqrt{%
x^{2}+1}}$ \ \ \ \ \ \ \ d) \ $\dfrac{\sqrt{1-x^{2}}}{x}$

\item see solutions

\item see solutions

\item a) \ $0$ \ \ \ \ b) \ $5$ \ \ \ c) \ $\dfrac{1}{6}$ \ \ \ \ d) \ $-%
\dfrac{1}{4}$ \ \ \ \ e) \ $\func{undefined}$ \ \ \ \ f) \ $-\infty $ \ \ \
\ g) $\ -\dfrac{2}{\pi }$ \ \ \ \ h) $\ -\infty $ \ \ \ \ i) \ \ $\dfrac{\pi 
}{2}$ \ \ \ \ j) \ $\dfrac{3}{2}$ \ \ \ \ 

k) \ $-\infty $ \ \ \ l) \ $1$

\item a) $y^{\prime }=\dfrac{-y^{2}+4x\left( x^{2}-y^{2}\right) ^{3}}{%
2xy+4y\left( x^{2}-y^{2}\right) ^{3}}$ \ \ \ \ \ \ \ \ \ \ b) \ $y^{\prime }=%
\dfrac{\cos x-3\left( x+y\right) ^{2}}{\cos y+3\left( x+y\right) ^{2}}$

\item see solutions

\item see solutions

\item a) \ $\tan ^{-1}x+C$ \ \ \ \ \ b) \ $x-\tan ^{-1}x+C$ \ \ \ \ \ \ \ \
\ c) \ $-\dfrac{1}{5}\cos 5x+C$ \ \ \ \ \ \ \ \ \ d) \ $-\ln \left\vert
-x+2\right\vert +C$

e) \ $\dfrac{\left( 3x-1\right) ^{11}}{33}+C$ \ \ \ \ \ \ f) \ $\dfrac{1}{3}%
\sin ^{-1}\left( 3x\right) +C$ \ \ \ \ \ \ \ \ \ g) \ $\ln \left\vert
x-5\right\vert +C$ \ \ \ \ \ \ \ \ h) \ $3x-2\ln \left\vert x-5\right\vert
+C $

i) \ $3x-2\ln \left\vert x-5\right\vert +C$

Solution for b): \ 
\begin{equation*}
\dint \dfrac{x^{2}}{x^{2}+1}dx=\dint \dfrac{x^{2}+1-1}{x^{2}+1}dx=\dint 
\dfrac{x^{2}+1}{x^{2}+1}-\dfrac{1}{x^{2}+1}dx=\dint 1-\dfrac{1}{x^{2}+1}%
dx=\dint 1dx-\dint \dfrac{1}{x^{2}+1}dx=x-\tan ^{-1}x+C
\end{equation*}

\item a) \ $\dfrac{\sqrt{3}}{4}a^{2}$ \ \ \ \ \ \ \ \ b) \ $\dfrac{\sqrt{3}}{%
3}h^{2}$ \ \ \ \ \ \ \ \ \ c) \ $4\sqrt{A}$ \ \ \ \ d) \ $\dfrac{1}{4}\pi
c^{2}$
\end{enumerate}

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\href{https://teaching.martahidegkuti.com/shared/lnotes/lecturenotes.html}{%
For more documents like this, visit our page at\
https://teaching.martahidegkuti.com and click on Lecture Notes. \ E-mail
questions or comments to mhidegkuti@ccc.edu.}

\end{document}
