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%TCIDATA{<META NAME="Title" CONTENT="Riemann Sums">}
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\lhead{\color{blue} \Large Practice}
\lfoot{\small   \copyright $\;$ copyright  Hidegkuti, 2012}
\rfoot{\small   Last revised:  April 22, 2014}
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\chead{\LARGE Riemann Sums}
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\begin{document}


\begin{enumerate}
\item Consider the function $f\left( x\right) =\ln x$ on the interval $\left[
1,6\right] .$\FRAME{dtbpFX}{4.1252in}{2.4734in}{0pt}{}{}{Plot}{\special%
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a) \ Approximate $\dint\limits_{1}^{6}\ln xdx$ by a left Riemann sum using a
uniform partition with $n=5$. \ Is this an underestimation or overestimation
of the area under the graph?

b) \ Approximate $\dint\limits_{1}^{6}\ln xdx$ by a right Riemann sum using
a uniform partition with $n=5$. \ Is this an underestimation or
overestimation of the area under the graph?

c) \ Approximate $\dint\limits_{1}^{6}\ln xdx$ by a left Riemann sum using a
uniform partition with $n=10$. \ Is this an underestimation or
overestimation of the area under the graph?

d) \ Approximate $\dint\limits_{1}^{6}\ln xdx$ by a right Riemann sum using
a uniform partition with $n=10$. \ Is this an underestimation or
overestimation of the area under the graph?\bigskip \pagebreak

\item Consider the function $f\left( x\right) =\sin x$ on the interval $%
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a) \ Compute the left Riemann sum for $\dint\limits_{0}^{\pi }\sin xdx$ on
this interval with $n=4$ subintervals. \ Make sure to use radians for angles.

b) \ Compute the left Riemann sum for $\dint\limits_{0}^{\pi }\sin xdx$ on
this interval with $n=4$ subintervals. \ Make sure to use radians for angles.

c) \ Compute the left Riemann sum for $\dint\limits_{0}^{\pi }\sin xdx$ on
this interval with $n=6$ subintervals. \ Make sure to use radians for angles.
\end{enumerate}

\pagebreak

\begin{center}
{\LARGE Answers\bigskip \bigskip }
\end{center}

\begin{enumerate}
\item a) \ $\ln 2+\ln 3+\ln 4+\ln 5=\ln 120\approx 4.\,\allowbreak 787\,492$
\ \ \ \ underestimate\qquad

b) \ $\ln 2+\ln 3+\ln 4+\ln 5+\ln 6=\ln 720\approx \allowbreak
6.\,\allowbreak 579\,25$ \ \ \ \ overestimate

c) $\ \allowbreak \dfrac{1}{2}\left( \ln \dfrac{2}{2}+\ln \dfrac{3}{2}+\ln 
\dfrac{4}{2}+\ln \dfrac{5}{2}+\ln \dfrac{6}{2}+\ln \dfrac{7}{2}+\ln \dfrac{8%
}{2}+\ln \dfrac{9}{2}+\ln \dfrac{10}{2}+\ln \dfrac{11}{2}\right) =\dfrac{1}{2%
}\ln \left( \dfrac{11!}{2^{10}}\right) \approx 5.\,\allowbreak 285\,418$ \ \
\ \ 

\qquad underestimate

d) \ $\allowbreak \dfrac{1}{2}\left( \ln \dfrac{3}{2}+\ln \dfrac{4}{2}+\ln 
\dfrac{5}{2}+\ln \dfrac{6}{2}+\ln \dfrac{7}{2}+\ln \dfrac{8}{2}+\ln \dfrac{9%
}{2}+\ln \dfrac{10}{2}+\ln \dfrac{11}{2}+\ln \dfrac{12}{2}\right) =\dfrac{1}{%
2}\ln \left( \dfrac{12!}{2^{11}}\right) =\allowbreak 6.\,\allowbreak
181\,297\,8$

\qquad overestimate

\item a) \ $\dfrac{1}{4}\pi +\dfrac{1}{4}\pi \sqrt{2}\approx \allowbreak
1.\,\allowbreak 896\,118\,897\,\allowbreak 937\,04$ \ \ \ \ \ \ \ \ \ b) \ \ 
$\dfrac{1}{4}\pi +\dfrac{1}{4}\pi \sqrt{2}\approx \allowbreak
1.\,\allowbreak 896\,118\,897\,\allowbreak 937\,04$

c) \ $\dfrac{1}{3}\pi +\dfrac{1}{6}\pi \sqrt{3}\approx \allowbreak
1.\,\allowbreak 954\,097\,233\,\allowbreak 313\,71$
\end{enumerate}

\vspace{6.2in}

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